In reality, a hydrate of iron(iii) nitrate had to be used, not the anhydrous salt. as you may guess, some of the hydrate’s mass is water, and some is iron(iii) nitrate. how many grams of fe(no3)3•9h2o needed to be dissolved in water to make 2 l of 0.0020 m fe(no3)3? molecular weight of the nonahydrate is 404.0 g/mol. hint: try to set up an equation using x, and solving it. assume that the density of your solution is 1.000 g/ml.
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