Chemistry, 08.10.2019 18:30, dinapearce6078

How is a yeast cell different from an onion skin cell? yeast can reproduce by budding. onion cells do not reproduce by budding. yeast lacks a membrane-bound nucleus. the onion skin cell has one. yeast has chloroplasts. the onion skin cell doesn't have chloroplasts. yeast lacks a cell membrane. an onion skin cell has a cell membrane.

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Yeast cell is different from an onion skin cell in that Yeast can reproduce by budding while onion skin cells do not reproduce by budding.

Explanation:

Reproduction is one of the characteristics of living organisms. All living organisms undertake reproduction to give rise to new organisms.There are two major types of reproduction namely asexual and sexual reproduction.Asexual reproduction is a form of reproduction that does not involve the fusion of gametes among organisms. Examples of asexual reproduction are budding in yeast and vegetative propagation in plants such as onions.Sexual reproduction, on the other hand, involves the fusion of gametes from male and female organisms which results in the formation of an embryo that develops to the fetus which becomes the offspring.Therefore, we could say that yeast cells reproduce asexually through budding while onions reproduce asexually through vegetative propagation.

answered: Guest

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form( $n_2$ ) .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

answered: Guest

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

$^{m}_{4}x$ and $^{m}_4y$

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

$^{m}_{5}x^{-}$

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be $^{9}_{5}be^{-}$ and $^{9}_{4}be$ .

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.

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How is a yeast cell different from an onion skin cell? yeast can reproduce by budding. onion cells...