38.0 ml of a 0.026 m solution of hcl is needed to react completely with a 0.032 m naoh solution. calculate the number of moles of hcl originally present

The number of mole of HCl originally present in the solution is 9.88×10¯⁴ mole

Molarity is defined as the mole of solute per unit litre of solution. Mathematically, it can be expressed as:

With the above information in mind, we can obtain the number of mole of HCl originally present in the solution. This is illustrated below:

Molarity of HCl = 0.026 M

Volume = 38 mL = 38 / 1000 = 0.038 L

Mole = Molarity × volume

Mole of HCl = 0.026 × 0.038

Thus, the number of mole of HCl originally present in the solution is 9.88×10¯⁴ mole

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The number of moles  of HCl actually present is 0.000988

Explanation:

The balanced chemical equation of the given reaction is

Here one mole of HCl reacts with one mole of NaOH to form one mole of NaCl and one mole of  water. Here the molarity of HCl is given as 0.026M.

molarity of NaOH is 0.032M

molarity is the number of moles per unit volume of solution.

we have to calculate the number of moles in 36 mL of HCl.

38 mL=36/1000=0.038L

the number of moles in 38 mL of HCl is given by

no of moles =

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.

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