Upon combustion, a 1.3109 g sample of a compound containing only carbon, hydrogen, and oxygen produces 3.2007 g[tex]co_{2}[/tex] and 1.3102 g[tex]h_{2}o[/tex]. find the empirical formula of the compound. the answer i got was [tex]ch_{16}o[/tex], but i'm not sure if i did it right or not. can someone confirm this for me?

Chemistry, 06.10.2019 03:20, ashleyuchiha123

Upon combustion, a 1.3109 g sample of a compound containing only carbon, hydrogen, and oxygen produces 3.2007 g $co_{2}$ and 1.3102 g $h_{2}o$ . find the empirical formula of the compound.

the answer i got was $ch_{16}o$ , but i'm not sure if i did it right or not. can someone confirm this for me?

Answers: 1

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Answers

answered: ashley232323

The answer to your question is: C₃H₃O This is my answer.

Explanation:

Data

Sample = 1.3109 g

CxHyOz

CO₂ = 3.2007 g

H₂O = 1.3102 g

Empirical formula = ?

MW CO2 = 44 g

MW H2O = 18 g

For Carbon

44 g 12 g

3.2007 g x

x = (3.2007 x 12) / 44

x = 0.8729 g of Carbon

12 g of C 1 mol

0.8729 g x

x = (0.8729 x 1) / 12

x = 0.0727 mol of Carbon

For Hydrogen

18 g 1 g

1.3102 g x

x = (1.3102 x 1) / 18

x = 0.0727 g of Hydrogen

1 g 1 mol

0.0727g x

x = (0.0727 x 1)/1

x = 0.0727 mol of Hydrogen

For oxygen

g of Oxygen = g of sample - g of Carbon - g of hydrogen

g of Oxygen = 1.3109 - 0.8709 - 0.0727

g of Oxygen = 0.3673

16 g of Oxygen 1 mol of O

0.3673 g x

x = (0.3673 x 1)/ 16

x = 0.0230 mol of Oxygen

Divide by the lowest number of moles

Carbon 0.0727 / 0.023 = 3.1 ≈ 3

Hydrogen 0.0727 / 0.023 = 3.1 ≈ 3

Oxygen 0.0230 / 0.023 = 1

C₃H₃O

answered: Guest

The correct answer is c

answered: Guest

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Upon combustion, a 1.3109 g sample of a compound containing only carbon, hydrogen, and oxygen produc...