The clown fish hides inside the poisonous tentacles of the sea anemone. since most other fish are unable to survive the anemone’s stings, the clown fish is protected from predators. in addition, it can feed on the leftovers from the anemone’s meals. this symbiotic relationship is called
a.
parasitism
b.
amensalism
c.
commensalism
d.
symbiosis

C: commensalism   please give me hearts and stars because the answer is right!!

Explanation:

The relationship between the clown fish and the deadly sea anemone can be classified as commensalism. Though the sea anemone’s tentacles are covered with thousands of nematocysts (tiny, venomous harpoons), the clown fish is protected by a thick coat of mucus and is not harmed by the anemone’s venom. The clown fish is therefore protected from predators and is also able to get leftover food from the anemone's meals. Since the clown fish ultimately benefits from this arrangement and the sea anemone neither benefits nor suffers because of the clown fish, the relationship is commensalistic.

considering the question as per the attachment

here we can see that the radon nuclide has 222 as the atomic mass number and 86 as the atomic number.

when it undergoes nuclear fission it gives polonium which has atomic mass number as 218 and atomic number will be 84 along with a helium nucleus which has 4 atomic mass number and 2 as its atomic number.

222 = 218 + 4 (atomic mass number)

86 = ? + 2; therefore ? = 86-2 = 84.

the atomic mass number of polonium will be 84.