Calculate the volume occupied by 0.845 mole of nitrogen gas, the pressure, and the temperature. find the volume.
given: n = 0.845 mol
p=1.37 atm
t=315k
find : volume

V = 15.9512 dm³

Explanation:

Given data:

Pressure = P = 1.37 atm

Temperature = T= 315 K

Number of moles of nitrogen= n = 0.845 mol

Volume = V = ?

Formula:

PV = nRT

Now we will put the values in equation.

V = nRT/ P

V = ( 0.845 mol× 0.0821 dm³.atm.K⁻¹.mol⁻¹ × 315 K) / 1.37 atm

V = 21.853 dm³. atm/  1.37 atm

V = 15.9512 dm³

The volume occupied by 0.845 mole of nitrogen gas is 15.9 L.

Explanation:

Given

N = 0.845 mol

P = 1.37 atm

T = 315 k

We make use of the Ideal gas equation to solve this problem

Ideal gas law equation is

PV=nRT

Rearranging the formula                  

Plugging in the values given we have

v = 15.9 L is the volume occupied by 0.845 mole of nitrogen gas.

answer: the rate of diffusion increases with increase in temperature.

increase in temperature, increases the molecular/particles speed (kinetic energy. diffusion means movement of particles through the material.

generally, the heavier the particle the more it interacts with the environment and more the temperature matters. so higher temperature results in higher diffusion.