For the reaction c2h4(g) + h2o(g) --> ch3ch2oh(g)

h° = -45.6 kj and s° = -125.7 j/k

the equilibrium constant for this reaction at 262.0 k is

Answer : The value of equilibrium constant for this reaction at 262.0 K is

Explanation :

As we know that,

where,

= standard Gibbs free energy  = ?

= standard enthalpy = -45.6 kJ = -45600 J

= standard entropy = -125.7 J/K

T = temperature of reaction = 262.0 K

Now put all the given values in the above formula, we get:

The relation between the equilibrium constant and standard Gibbs free energy is:

where,

= standard Gibbs free energy  = -12666.6 J

R = gas constant  = 8.314 J/K.mol

T = temperature  = 262.0 K

K = equilibrium constant = ?

Now put all the given values in the above formula, we get:

Therefore, the value of equilibrium constant for this reaction at 262.0 K is

question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

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(jacemorris04)