Etermine the percent yield of the following reaction when 2.80 g of p reacts with excess oxygen. the actual yield of this reaction is determined to by 3.89 g of p2o5.
4 p+5o2→2p2o5

Yield = 66.7%

Explanation:

4P + 5O₂ → 2P₂O₅

P: 31 g/mol

O₂: 32 g/mol

P₂O₅: 142 g/mol

31 g P 1 mol

2.80 g P __     x

  x = 0.09 mol P

142 g P₂O₅ 1 mol

3.89 g P₂O₅ ___     y

     y = 0.03 mol P₂O₅

In a 100% yield, 4 mol of P produces 2 mol of P₂O₅. 0.09 of P should, therefore, produce 0.045 mol of P₂O₅.

Yield = (0.03 mol / 0.045 mol) x 100

Yield = 66.7%

answer

i think the answer is a) as air pressure in an area increases, the density of the gas particles in that area decreases.

hope it

i'm pretty sure it is letter c.) car