Calculate the equilibrium concentrations of n2o4 and no2 at 25 ∘c in a vessel that contains an initial n2o4 concentration of 0.0654 m . the equilibrium constant kc for the reaction n2o4(g)⇌2no2(g) is 4.64×10−3 at 25 ∘c.

The equilibrium concentration of are 0.0164 M and 0.0572 M

Explanation:

We are given:

Initial concentration of = 0.0654 M

The given chemical equation follows:

Initial:         0.0654

At eqllm:   0.0654 - x           2x

The expression of for above reaction follows:

We are given:

Putting values in above equation, we get:

Solving for the value of 'x', we get:

Neglecting the negative value of 'x', as concentration cannot be negative.

Now,

Hence, the equilibrium concentration of are 0.0164 M and 0.0572 M