Astudent is extracting caffeine from water with dichloromethane. the k value is 4.6. if the student starts with a total of 40 mg of caffeine in 2 ml of water and extracts once with 6 ml of nioromethane, how much caffeine will be in the dichloromethane extract? show all work.

Explanation:

The given value of K = 4.6

As before extraction, 40 mg of caffeine in 2 ml of water.

Hence, after the first extraction,

               4.6 =

                = 7.2 mg

Therefore, caffeine extracted from dichloromethane is as follows.

                     40 mg - 7.2 mg = 32.8 mg

Now, after the second extraction

                 4.6 =

                  = 1.29 mg

So,                (7.2 - 1.29) mg = 5.91 mg

This means that 5.91 mg of caffeine is extracted from dichloromethane.

After the third extraction,

                 4.6 =

                      = 0.229 mg

Hence, caffeine extracted from dichloromethane is as follows.

                             (1.29 - 0.229) mg

                            = 1.061 mg

Therefore, we can calculate the total amount of caffeine extracted as follows.

      Total caffeine extracted = 40 - caffeine remains in dichloromethane after three extraction

                                              = 40 - 0.229

                                              = 39.771 mg

Thus, we can conclude that the total extracted caffeine is 39.771 mg.                                    

the grams   of   barium that   are in   2.3 x 10^23   atoms of barium   is   52.4 g (answer c)

    calculation

mass = moles   of ba   x molar   mass of ba

  molar mass of ba from periodic table=   137.3 g/mol

  use the   avogadro's law   constant   to   calculate the moles of barium

  that   is     1 mole =   6.02   x 10^23 atoms

                    ? moles = 2.3 x 10^23   atoms

by cross   multiplication

=(1 mole   x 2.3x 10^23 atoms)   / 6.02   x10^23 atoms)=   0.382   moles

mass   is therefore = 137.3   g/mol x 0.382 mol = 52.4 ( answer c)

explanation:

can you attach the