Both kbr and nabr are soluble ionic compounds and fully dissociate in aqueous solution. a 21.545-g mixture of kbr and nabr is dissolved in water, then a solution of agno3 is added so that all of the bromine present is converted to solid agbr. the agbr product is dried and found to have a mass of 35.593 g. what mass of kbr was present in the original mixture?

Explanation:

Let the molar mass of KBr is and NaBr is .

In 21.545 g, the moles of KBr and NaBr are and .

Therefore,   = 21.545 g

Mass of AgBr is 35.593 g.

            = 35.593 g

    = 35.593 g

        = 35.593 g

Now, putting the given values into the above formula as follows.

                    =

                    =

                    = 0.224 mol

Hence, mass of KBr will be calculated as follows.

                          = 26.656 g

Thus, we can conclude that mass of KBr present in the original mixture is 26.656 g.

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :