Each step in the process below has 80% yield.
ch4+4cl2 > ccl4+4hcl
ccl4+2hf --> ccl2f2+2hcl
the ccl4 formed in the first step is used as a reactant in the second step.
if 2.00 mol of ch4 reacts, what is the total amount of hcl produced? assume that cl2 and hf are present in the excess.
explain
Answers: 2
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Each step in the process below has 80% yield.
ch4+4cl2 > ccl4+4hcl
ccl4+2hf -->...
ch4+4cl2 > ccl4+4hcl
ccl4+2hf -->...
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