Ag' for the isomerization reaction glucose-1-phosphate (gip) $ glucose-6-phosphate (g6p) is -7.1 kj/mol. calculate the equilibrium ratio of [g1p] to (g6p) at 25°c. read this carefully to make sure you solve for the correct ratio! show work! [g1p][g6p] =

The ratio [G1P]/[G6P] = 5.7 . 10⁻².

Explanation:

Let us consider the reaction G1P ⇄ G6P, with ΔG° = -7.1 kJ/mol. According to Hess's Law, we can write the inverse reaction, and Gibbs free energy would have an opposite sign.

G6P ⇄ G1P        ΔG° = 7.1 kJ/mol

This is the reaction for which we want to find the equilibrium constant (the equilibrium ratio of [G1P] to [G6P]):

The equilibrium constant and Gibbs free energy are related by the following expression:

where,

R is the ideal gas constant (8.314 . 10⁻3 kJ/mol.K)

T is the absolute temperature (in kelvins)