Chemistry, 28.09.2019 01:30, cw1242605

How many grams of testosterone, c19h28o2 (288.4 g/mol), must be dissolved in 299.0 grams of benzene to reduce the freezing point by 0.500°c ? refer to the table for the necessary boiling or freezing point constant.

solvent

formula

kb (°c/m)

kf (°c/m)

water

h2o

0.512

1.86

ethanol

ch3ch2oh

1.22

1.99

chloroform

chcl3

3.67

benzene

c6h6

2.53

5.12

diethyl ether

ch3ch2och2ch3

2.02

? g testosterone.

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How many grams of testosterone, c19h28o2 (288.4 g/mol), must be dissolved in 299.0 grams of benzene...