2ki + pb(no3)2 → 2kno3 + pbi2 determine how many grams of ki are required to produce 1.2g of pbi2.

Molar mass KI = 166.0028 g/mol   and Pbl₂ = 461.0089 g/mol

2 Kl + Pb(NO₃)₂ > 2 KNO₃ + Pbl₂

2 x 166.0028 g > 461.0089 g
           ? g KI > 1.2 g

Mass KI = 1.2 x 2 x 166.0028 / 461.0089

Mass KI = 398.40672 / 461.0089

Mass KI = 0.86 g

hope this helps!

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