When a 7.00 g7.00 g sample of kbrkbr is dissolved in water in a calorimeter that has a total heat capacity of 2.72 kj⋅k−1,2.72 kj⋅k−1, the temperature decreases by 0.430 k.0.430 k. calculate the molar heat of solution of kbr.

Answer : The molar heat of solution of KBr is 19.9 kJ/mol

Explanation :

Mass of KBr = 7.00 g

Molar mass of KBr = 119 g/mole

Heat capacity = 2.72 kJ/K

Change in temperature = 0.430 K

First we have to calculate the moles of KBr.

Now we have to calculate the heat of the reaction.

where,

q = amount of heat = ?

= heat capacity =

= change in temperature = 0.430 K

Now put all the given values in the above formula, we get:

Now we have to calculate the molar heat of solution of KBr.

where,

n = number of moles of KBr

Therefore, the molar heat of solution of KBr is 19.9 kJ/mol

- lead + phosphoric acid = hydrogen + lead(ii) phosphate