Pure nitrogen (n2) and pure hydrogen (h2) are fed to a mixer. the product stream has 40.0% mole nitrogen and the balance hydrogen. the product flow rate is 1,368 kg/hr. calculate the feed rate of pure nitrogen to the mixer in kg/hr.

Explanation:

The given data is as follows.

        Mass flow rate of mixture = 1368 kg/hr

      in feed = 40 mole%

This means that in feed = (100 - 40)% = 60%

We assume that there are 100 total moles/hr of gas in feed stream.

Hence, calculate the total mass flow rate as follows.

           40 moles/hr of N_{2}/hr (28 g/mol of ) + 60 moles/hr of (2 g/mol of )

                  = 1120 g/hr + 120 g/hr

                  = 1240 g/hr

                  =              (as 1 kg = 1000 g)

                  = 1.240 kg/hr

Now, we will calculate mol/hr in the actual feed stream as follows.

                   = 110322.58 moles/hr

It is given that amount of nitrogen present in the feed stream is 40%. Hence, calculate the flow of into the reactor as follows.

                      = 44129.03 mol/hr

As 1 mole of nitrogen has 28 g/mol of mass or 0.028 kg.

Therefore, calculate the rate flow of into the reactor as follows.

                         = 1235.612 kg/hr

Thus, we can conclude that the the feed rate of pure nitrogen to the mixer is 1235.612 kg/hr.

in chemistry, adhesion and cohesion are attractive forces that exist between molecules. they hold the molecules together from each other. they are different in that adhesive force exists between molecules of different substance while cohesive force happens between molecules of same substance.

adhesion between water and glass causes water molecules at the edge of water and glass interface to climb up the wall in a narrow glass tube. this is called capillary action. cohesion is what gives glass its shape and causes water to form a droplet.