As accurately as possible find the residual molar volume of saturated liquid water at 83 bar.

v = 2.512 E-5 m³/mol

Explanation:

∴ P = 80 bar → V = 0.001384 m³/Kgsat. liq water table

∴ P = 85 bar → V = 0.0014013 m³/Kg

⇒ P = 83 bar → V = ?

specific volume ( V ):

⇒ V = 0.001384 + (( 83 - 80 ) / ( 85 - 80 ))*( 0.0014013 - 0.001384 )

⇒ V = 0.00139438 m³/Kg

molar volume ( v ):

∴ Mw water = 18.01528 g/mol

⇒ v = 0.00139438 m³/Kg * ( Kg/1000g ) * ( 18.01528 g/mol )

⇒ v = 2.512 E-5 m³/mol

law of conservation of matter

water at room temperature is flowing through a pipe with pressure taps located 10 ft apart along one section of the pipe, which are connected to a mercury (s=13.6) manometer.