1kg of oxygen gas is present in a 500 l tank. find the specific and molar volumes of the gas.

specific volume O2 = 0.5 Kg/m³

molar volume O2 = 8 E-3 m³/mol

Explanation:

specific volume (Sv):

∴ Sv = 1 / ρ

∴ ρ = mass / volume

∴ V = 500 L * ( m³/1000 L) = 0.5 m³

∴ ρ = 1 Kg / 0.5m³ = 2 Kg/m³

⇒ Sv = 1 / 2 Kg/m³ = 0.5 m³/Kg

molar volume ( Vm ):

∴ Vm = volume/mol

∴ Mw O2 = 1000g O2 * ( mol/16g O2) = 62.5 mol O2

⇒ Vm = 0.5 m³ / 62.5 mol

⇒ Vm = 8 E-3 m³/mol