Glass vessel calibrated to contain 9.76 ml of water at 4°c was found to weigh 22.624 g when empty and dry feel the weight of sodium chloride solution at the same temperature it was found to weigh 32.770 g calculate the solutions density

This is the complete question with grammar corrections:

A glass vessel calibrated to contain 9.76 mL at 4° C was found to weigh 22.624 g when empty and dry. Filled with a soduim chloride (NaCl) solution at the same temperature , it was found to weigh 32.770 g. Calculate the solution's density.

Explanation:

Density is the physical property that expresses the amount of matter (mass) per voumetric unit of solution:

In this problem, you can first calculate the mass, by difference. After that, you just have to divide the mass by the volume of the glass vessel (9.76 ml as per the calibration).

This is the two steps procedure.

1. Mass of the solution:

       Mass of solution = 32.770 g - 22.624 g = 10.146 g

2. Solution's density:

The density is rounded to 3 significant digits because the volume, which is dividing the mass, was reported with 3 significant digits.

The solution density will be 1.04 g/mL

Explanation:

Mass of the solution = mass of the glass vessel with NaCl solution – mass of the empty glass vessel

= 32.770 g - 22.624 g

= 10.146 g

Volume of the solution = 9.76 mL

Thus, the solution density will be 1.04 g/mL.

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml