Answers: 1
Chemistry, 21.06.2019 17:10, codeyhatch142
Nitric oxide (no) can be formed from nitrogen, hydrogen and oxygen in two steps. in the first step, nitrogen and hydrogen react to form ammonia: n2(g) + 2 h_2(g) rightarrow 2 nh_3 (g) delta h = -92. kj in the second step, ammonia and oxygen react to form nitric oxide and water: 4 nh_3(g) + 5 o_2(g) rightarrow 4no(g) + 6 h_2o(g) delta h = -905. kj calculate the net change in enthalpy for the formation of one mole of nitric oxide from nitrogen, hydrogen and oxygen from these reactions. round your answer to the nearest .
Answers: 1
Chemistry, 22.06.2019 17:10, sophiaa23
)benzene and toluene form nearly ideal solutions. consider an equimolar solution of benzene and toluene. at 20 Β°c the vapour pressures of pure benzene and toluene are 9.9 kpa and 2.9 kpa, respectively. the solution is boiled by reducing the external pressure below the vapour pressure. calculate (i) the pressure when boiling begins, (ii) the composition of each component in the vapour, and (iii) the vapour pressure when only a few drops of liquid remain. assume that the rate of vaporization is low enough for the temperature to remain constant at 20 Β°c.
Answers: 1
Chemistry, 22.06.2019 23:50, josie311251
Be sure to answer all parts. the following equilibrium constants were determined at 1123 k: c(s) + co2(g) β 2co(g) k'p = 1.30 Γ 1014 co(g) + cl2(g) β cocl2(g) k''p = 6.00 Γ 10β3 calculate the equilibrium constant at 1123 k for the reaction: c(s) + co2(g) + 2cl2(g) β 2cocl2(g) 4.68 Γ 10 9 (enter your answer in scientific notation.) write the equilibrium constant expression, kp:
Answers: 3
Consider the following energy diagram.
activation complex
actual
reaction
en...
activation complex
actual
reaction
en...
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