For every 5.00 ml of milk of magnesia there are 400. mg of magnesium hydroxide. how many ml of milk of magnesia do we need to neutralize 40.0 ml of 0.500 m hcl? express your answer in ml

The volume of magnesium hydroxide needed to neutralize the given amount of HCl is 7.29 mL

Explanation:

To calculate the number of moles for given molarity, we use the equation:

Molarity of HCl = 0.500 M

Volume of solution = 40 mL

Putting values in above equation, we get:

The chemical equation for the reaction of magnesium hydroxide and hydrochloric acid follows:

By Stoichiometry of the reaction:

2 moles of HCl reacts with 1 mole of magnesium hydroxide.

So, 0.02 moles of HCl will react with = of magnesium hydroxide

Molar mass of magnesium hydroxide = 58.32 g/mol

Moles of magnesium hydroxide = 0.01 moles

Putting values in equation 1, we get:

We are given:

Mass of magnesium hydroxide = 400 mg = 0.4 g    (Conversion factor: 1 g = 1000 mg)

To calculate the volume of magnesium hydroxide needed to neutralize, we use unitary method:

For 0.4 g of magnesium hydroxide, the volume occupied is 5.00 mL

So, for 0.5832 g of magnesium hydroxide, the volume occupied will be =

Hence, the volume of magnesium hydroxide needed to neutralize the given amount of HCl is 7.29 mL

1 a

2 d

3 a

4 c

explanation:

frequency, z, and the collision density, z, in carbon dioxide (co2), r 180 pm at 30 °c and 120 kpa