The fuel used in many disposable lighters is liquid butane, c4h10. how many carbon atoms are in 2.00 g of butane?

The answer to your question is: 8.31 x 10 ²² atoms

Explanation:

butane C₄H₁₀  

carbon atoms in 2 g of butane

MW C₄H₁₀ = (4 x 12) + (1 x10) = 48 + 10 = 58 g

                        58 g of butane  48 g of C

                          2 g of butane      x

                     x = (2 x 48) / 58 = 1.655 g of C

                         1 mol C 12 g

                          x            1.655 g

                         x = (1.655 x 1) / 12 = 0.14 mol of C

                     1 mol of C 6.023 x 10 ²³ atoms

                    0.14 mol of C     x

                        x = ( 0.14 x 6.023 x 10 ²³) / 1

                       x = 8.31 x 10 ²² atoms

i do not get it   at all