Chemistry, 20.09.2019 00:00, jgunt8277

Which of the following is true about oxygen (o), sulfur (s) and neon (ne)? (choose 3)
a. oxygen and neon are in the same group and have the same number of valence electrons.
b. oxygen and sulfur are in the same period and have the same number of electron shells.
c. oxygen and neon are in the same period and have the same number of electron shells.
d. oxygen and sulfur have the same number of valence electrons.
e. oxygen and sulfur are most similar because they are in the same family and have similar chemical properties.
f. oxygen and neon have similar chemical properties.

Which of the following is true about oxygen (o), sulfur (s) and neon (ne)? (choose 3)

Answers: 1

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answered: twistedhyperboles

from the way I understand the question I think the answer is (B)

Explanation:

Because the distribution into shells of oxygen is 2,6 and in sulfur is 2,8,6 and oxygen has a 8th number of electrons and sulfur has the 16th number of electrons

answered: Bgreene2377

Option C, option D and option E is correct

Explanation:

Atomic number of O = 8

Electronic configuration of O = 1s^22s^22p^4

No. of valence electron = 6

Atomic number of S = 16

Electronic configuration of O = 1s^22s^22p^63s^23p^4

No. of valence electron = 6

Atomic number of Ne = 10

Electronic configuration of Ne = 1s^22s^22p^6

No. of valence electron = 8

No. of electron shell present in any atom is equal to principle quantum no.

So, no. of electron shell in O = 2

no. of electron shell in S = 3

no. of electron shell in Ne = 2

O is present in period 2 and group 16.

S is present in period 3 and group 16.

Ne is present in period 2 and group 16.

So, O and S are present in same group. Elements of same group or family display similar chemical properties.

So, among correct options are:

option C: Oxygen and Neon are in the same period and have the same number of electron shells.

Option D: Oxygen and Sulfur have the same number of valence electrons.

Option E: Oxygen and Sulfur are most similar because they are in the same family and have similar chemical properties.

answered: Guest

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = $25^oc$ = 298 k $)0^oc=273kelvins$

$o_3+3no\rightarrow 3no_2,\delta h_{reaction}=? [/)</p><p>[tex]\delta h_{no}=90.4kj/mol$

$\delta h_{no_2}=33.85kj/mol$

$\delta h_{o_3}=142.2kj/mol$

$\delta h_{reaction}=\sum \delta h_{products}-\sum\delta h_{reactants}=3\times\delta h_{no_2}-(3\times \delta h_{no}+\delta h_{o_3})$

$\delta h_{reaction}=33.85-(90.4+142.2)=-311.85kj/mol$

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

$v_{no}=12.00 l,v_{o_3}=8.50 l$

$pv_{no}=n_{no}rt=1atm \times 12.00 l=n_{no}\times 0.0821 atml/k mol \times 298 k$

$n_{no}=0.49 moles$

$pv_{o_3}=n_{o_3}rt=1atm \times 8.50 l=n_{o_3}\times 0.0821 atml/k mol \times 298 k$

$n_{o_3}=0.34 moles$

according to reaction 3 moles no are reacting with 1 mol of $o_3$ ,then 0.49 mol of no will react with $\frac{1}{3}\times 0.49$ moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and $o_3$ is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :

$\delta h_{reaction}\times \text{moles of no}=-311.85kj/mol\times 0.49 mol=-152.80kj/mol$

answered: Guest

answers: to make sure that all of the broken pieces of tablet were added to the water, to allow for fair comparison of all three trials, with different particle sizes to avoid experimental error

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Which of the following is true about oxygen (o), sulfur (s) and neon (ne)? (choose 3)
a. oxyg...