When 282 gr of glycine are dissolved in 950 gr of a certain mystery liquid, the freezing point of the solution is 8.2 c less than the freezing point of pure. calculate the mass of iron(iii) chloride that must be dissolved in the same mass of to produce the same depression in freezing point. the van't hoff factor for iron(iii) chloride in x. be sure your answer has a unit symbol, if necessary, and round your answer to significant digits.

Explanation:

Depression in freezing point is given by:

= Depression in freezing point

i= vant hoff factor = 1 (for non electrolyte like glycine)

= freezing point constant = ?

m= molality

Weight of solvent = 950 g = 0.95 kg

Molar mass of glycine = 75.07 g/mol

Mass of glycine added = 282 g

Thus freezing point constant is

2)

= Depression in freezing point

i= vant hoff factor = 4 (for )

= freezing point constant =

m= molality  

Weight of solvent = 950 g = 0.95 kg

Molar mass of = 162.2 g/mol

Mass of   added = ?

Thus mass of iron(III) chloride that must be dissolved in the same mass of to produce the same depression in freezing point is

i believe it is-

d.) gravity pulled particles of dust and gas together to form planets.

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

            and  

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be and .  

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.