Chemistry, 19.09.2019 04:30, friendsalwaysbae

Homework 3 write the balanced equations. calculate how many grams of each reactant will be needed to obtain 100.0 grams of the insoluble product formed in the reaction. show complete solutions. 1. aluminum chloride + calcium hydroxide  aluminum hydroxide + calcium chloride 2. mercury (ii) oxide  mercury + oxygen 3. barium nitrate + copper (ii) sulfate  barium sulfate+ copper (ii) nitrate 4. lead (ii) chloride + potassium iodide  lead (ii) iodide + potassium chloride 5. sodium sulfide + copper (ii) chloride  copper (ii) sulfide + sodium chloride

Answers: 2

Show answers

Answers

answered: kayleedavis08

1. 170,9 g of AlCl₃ and 142,5 g of Ca(OH)₂

2. 108,0 g of HgO

3. 112,0 g of Ba(NO₃)₂ and 68,39 g of CuSO₄

4. 60,32 g of PbCl₂ and 72,01 g of KI

5. 81,63 g of Na₂S and 140,6 g of CuCl₂

Explanation:

1. The reaction is:

2 AlCl₃ + 3 Ca(OH)₂ → 2 Al(OH)₃ + 3 CaCl₂

The insoluble product is Al(OH)₃. To produce 100,0 g you need to add:

100,0 g × $\frac{1 mol}{78 g}$ = 1,282 moles of Al(OH)₃.

Thus, the grams of AlCl₃ and Ca(OH)₂ you need are:

1,282 moles of Al(OH)₃ × $\frac{2 AlCl_3 moles}{2 Al(OH)_3 moles}$ = 1,282 moles of AlCl₃ × $\frac{133,34 g}{1 mol}$ = 170,9 g of AlCl₃

1,282 moles of Al(OH)₃ × $\frac{3 Ca(OH)_2 moles}{2 Al(OH)_3 moles}$ = 1,923 moles of Ca(OH)₂ × $\frac{74,093 g}{1 mol}$ = 142,5 g of Ca(OH)₂

2. The reaction is:

2 HgO + → 2 Hg + O₂

The insoluble product is Hg. To produce 100,0 g you need to add:

100,0 g × $\frac{1 mol}{200,59 g}$ = 0,4985 moles of Hg.

Thus, the grams of HgO you need are:

0,4985 moles of Hg × $\frac{2 HgO moles}{2 Hg moles}$ = 0,4985 moles of HgO × $\frac{216,59 g}{1 mol}$ = 108,0 g of HgO

3. The reaction is:

Ba(NO₃)₂ + CuSO₄ → BaSO₄ + Cu(NO₃)₂

The insoluble product is BaSO₄. To produce 100,0 g you need to add:

100,0 g × $\frac{1 mol}{233,38 g}$ = 0,4285 moles of BaSO₄.

Thus, the grams of Ba(NO₃)₂ and CuSO₄ you need are:

0,4285 moles of BaSO₄ × $\frac{1 Ba(NO_{3})_2 moles}{1 BaSO₄ moles}$ = 0,4285 moles of Ba(NO₃)₂ × $\frac{261,337 g}{1 mol}$ = 112,0 g of Ba(NO₃)₂

0,4285 moles of BaSO₄ × $\frac{1 CuSO_4 moles}{1 BaSO_4 moles}$ = 0,4285 moles of CuSO₄ × $\frac{159,609 g}{1 mol}$ = 68,39 g of CuSO₄

4. The reaction is:

PbCl₂ + 2 KI → PbI₂ + 2 KCl

The insoluble product is PbI₂. To produce 100,0 g you need to add:

100,0 g × $\frac{1 mol}{461,01 g}$ = 0,2169 moles of PbI₂.

Thus, the grams of PbCl₂ and KI you need are:

0,2169 moles of PbI₂ × $\frac{1 PbCl_2 moles}{1 PbI_2 moles}$ = 0,2169 moles of PbCl₂ × $\frac{278,1 g}{1 mol}$ = 60,32 g of PbCl₂

0,2169 moles of PbI₂ × $\frac{2 KI moles}{1 PbI_2 moles}$ = 0,4338 moles of KI × $\frac{166,0028 g}{1 mol}$ = 72,01 g of KI

5. The reaction is:

Na₂S + CuCl₂ → CuS + 2 NaCl

The insoluble product is CuS. To produce 100,0 g you need to add:

100,0 g × $\frac{1 mol}{95,611 g}$ = 1,046 moles of CuS.

Thus, the grams of Na₂S and CuCl₂ you need are:

1,046 moles of CuS × $\frac{1 Na_{2}S moles}{1 CuS moles}$ = 1,046 moles of Na₂S × $\frac{78,0452 g}{1 mol}$ = 81,63 g of Na₂S

1,046 moles of CuS × $\frac{1 CuCl_2 moles}{1 CuS moles}$ = 1,046 moles of CuCl₂ × $\frac{134,45 g}{1 mol}$ = 140,6 g of CuCl₂

I hope it helps!

answered: Guest

c. heat could easily travel through the molecules in the air and escape/enter the flask. removing the air slows down the heat transfer.

answered: Guest

Mass is the amount of matter in an object. weight is the measurement of the pull of gravity on an object. say for example, you travel to the moon which has a different gravitational field compared to the gravitational field of earth. (gravitational fields: earth = 1, moon = 0.165) now when you are on the moon, the pull of gravity on you is different than on the earth. and as weight is the measurement of the pull of gravity on an object, that means yes, your weight can and will change on the moon. however, on the moon, on earth or even on jupiter, the amount of mass inside of you remains the same. meaning your physical mass remains constant. in conclusion it is possible for your weight to change as your mass remains constant.

Other questions on the subject: Chemistry

Chemistry, 22.06.2019 01:30, jusicca1109

100 points answer quick the table compares the number of electrons in two unknown neutral atoms. comparison of electrons atom number of electrons a 10 d 11 use this information to determine the number of valence electrons in the atoms. which of the following correctly compares the stability of the two atoms? both are unreactive. both are highly reactive. a is unreactive and d is reactive. a is reactive and d is unreactive.

Answers: 1

continue

Chemistry, 22.06.2019 07:30, SchoolFirst9811

The scheme below is from a series of reactions that are part of a synthesis of vitamin a. answer the following questions with reference to this scheme. (i) what is "reagent a"? (ii) draw a step-by-step mechanism which explains the formation of compound c from compound b (iii) which reagents would you use to form compound e from compounds c and d (reagents b and c)? for each reagent suggested above in (ii) explain the role of the reagent in the reaction to (iv) form compound e. you may wish to do this by drawing a mechanism. 1. addition of reagent a но reagent a 2. н, о" thо oh нон-с compound a. compound b. compound c .ch-оh 1. reagent b "сно 2. reagent c сh oh compound e. compound d.

Answers: 2

continue

Chemistry, 22.06.2019 12:20, missayers172

Achemistry student weighs out 0.306 g of citric acid (h3c6h5o7), a triprotic acid, into a 250 ml volumetric flask and dilutes to the mark with distilled water. he plans to titrate the acid with 0.1000 m naoh solution. calculate the volume of naoh solution the student will need to add to reach the final equivalence point. be sure your answer has the correct number of significant digits.

Answers: 3

continue

Chemistry, 22.06.2019 13:00, Tanya120

Tell me the iupac names of the following alcohols:

Answers: 2

continue

Do you know the correct answer?

Homework 3 write the balanced equations. calculate how many grams of each reactant will be needed to...