Asample of liquefied natural, lng, from alaska has the following molar composition: 3.9% c2h6, 1.1% c3h8, 1.1% co2, and the rest ch4. determine (a) the average molecular weight of the lng mixture. (b) the weight fraction of ch4 in the mixture. (c) the lng is heated to 422 k and 148 kpa, and vaporizes completely. estimate the density of the gas mixture under these conditions.

a) 17,20

b) 87,57%

c) 0,7259

Explanation:

a) With molar composition of LNG the average molecular weight is:

3,9%×30,07 + 1,1%×44,1 +1,1%×44,01 + 93,9%×16,04 = 17,20

b) The weight fraction of CH₄ is:

×100 = 87,57%

c) It is possible to use ideal gas law thus:

= δ

Where:

P is pressure: 148 kPa

MW is molecular weight: 17,20

R is gas constant: 8,31

T is temperature: 422K.

And δ is density. Replacing you will obtain:

δ = 0,7258

I hope it helps!

answer; talc and gypsum;

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied