Chemistry, 17.09.2019 23:30, jake2920

A1.1000 gram carbonate sample chosen from li2co3, k2co3, na2co3 and caco3 was reacted with h2so4 and was found to lose 0.3497 gram of co2. (1) show the calculation of the % co2 in the unknown carbonate sample. (2) show the calculation of the % co2 in each of the carbonate compounds and identify the unknown carbonate from the list. atomic weights: c = 12.01, o = 16.00. mws: li2co3 = 73.892, k2co3 = 138.21, na2co3 = 105.99 and caco3 = 100.09

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answered: jamtil7937

For 1: The percentage composition of CO_2 in unknown carbonate sample is 31.79 %

For 2: The unknown carbonate sample is potassium carbonate.

Explanation:

To calculate the percentage composition of carbon dioxide in sample, we use the equation:

$\%\text{ composition of }CO_2=\frac{\text{Mass of }CO_2}{\text{Mass of sample}}\times 100$ .....(1)

For 1:

Mass of sample = 1.1000 g

Mass of carbon dioxide = 0.3497 g

Putting values in equation 1, we get:

$\%\text{ composition of }CO_2=\frac{0.3497g}{1.1000g}\times 100=31.79\%$

Hence, the percentage composition of CO_2 in unknown carbonate sample is 31.79 %

For 2:

We are given:

Mass of carbon dioxide = $[1\times 12.01)+(2\times 16.00)]=44.01g$

For lithium carbonate:

Mass of lithium carbonate= 73.892 g

Mass of carbon dioxide = 44.01 g

Putting values in equation 1, we get:

$\%\text{ composition of }CO_2=\frac{44.01g}{73.892g}\times 100=59.55\%$

The percent composition of carbon dioxide in lithium carbonate is 59.55 %

For potassium carbonate:

Mass of potassium carbonate= 138.21 g

Mass of carbon dioxide = 44.01 g

Putting values in equation 1, we get:

$\%\text{ composition of }CO_2=\frac{44.01g}{138.21g}\times 100=31.84\%$

The percent composition of carbon dioxide in potassium carbonate is 31.84 %

For sodium carbonate:

Mass of sodium carbonate= 105.99 g

Mass of carbon dioxide = 44.01 g

Putting values in equation 1, we get:

$\%\text{ composition of }CO_2=\frac{44.01g}{105.99g}\times 100=41.52\%$

The percent composition of carbon dioxide in sodium carbonate is 41.52 %

For calcium carbonate:

Mass of calcium carbonate = 100.09 g

Mass of carbon dioxide = 44.01 g

Putting values in equation 1, we get:

$\%\text{ composition of }CO_2=\frac{44.01g}{100.09g}\times 100=43.97\%$

The percent composition of carbon dioxide in calcium carbonate is 43.97 %

As, the percent composition of carbon dioxide in the unknown sample matches the percent composition of carbon dioxide in potassium carbonate.

Hence, the unknown carbonate sample is potassium carbonate.

answered: Guest

when atmosphere interacts with biosphere they focuses on on the sources and sinks of green house gases (ghgs) air pollutants, particular matters, water and energy between the earth's surface and the atmosphere. the biosphere affects the climate. the atmosphere and biosphere are in constant interaction with each other, and all living things rely on gases in the atmosphere for life. organisms such as animals take in oxygen gas form the atmosphere to use in every cell of their body for smooth functioning of daily routine exercises.

What happens when the atmosphere interacts with biosphere

answered: Guest

i think it's c. i'm not sure but i think so.

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