To analyze the experiment used to determine the properties of an electron. in 1909, robert millikan performed an experiment involving tiny, charged drops of oil. the drops were charged because they had picked up extra electrons. millikan was able to measure the charge on each drop in coulombs. here is an example of what his data may have looked like.
drop charge (c)
a 3.20 x 10^{-19}
b 4.80 x 10^{-19}
c 8.00 x 10^{-19}
d 9.60 x 10^{-19}
based on the given data, how many extra electrons did drop c contain?

Considering the data, drop C contained 5 extra electrons.

Explanation:

Robert Millikan and his colleague Harvey Fletcher puplished in 1911 a work in which they discribed an experiment that lead to the measurement of the elementary charge (e). These scientists determined that each electron has a charge equal to 1.60217662 × 10⁻¹⁹ coulombs.

Considering that each oil drop is neutral, the charge observed is due to extra electrons. Therefore, in order to determine the number of extra electrons (n) we need do divide the drop charge C by the elementary charge (e):

n = 8.00x10⁻¹⁹/1.60217662 × 10⁻¹⁹

n = 5 extra electrons.

the answer is the first option

explanation:

just googled it m8. not that hard

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the potential energy of the reactants is 200j.

from the energy diagram, the energy of the product formed is 350j; this means that, this reaction is an endothermic reaction, because it absorbs energy from its environment.