2.50 mole sample of an ideal gas, for which , is subjected to two successive changes in state: (1) from 25.0°c and , the gas is expanded isothermally against a constant pressure of to twice the initial volume. (2) at the end of the previous process, the gas is cooled at constant volume from 25.0°c to –29.0°c. calculate q, w, , and for each of the stages. also calculate q, w, , and for the complete process

(1) W = - 4293.3 J; Q = 4293.3 J

(2) W = 0 J; Q = - 1683.585 J

(3) Wt = -4293.3 J; Qt = 2609.72 J

Explanation:

(1) ΔU = 0

⇒ Q = - W

⇒ W = - ∫PdV

∴P = nRT/V

⇒ W = - nRT ∫dV/V

⇒ W = - nRT Ln (Vf/Vi) = - nRT Ln(2Vi/Vi) = - nRT Ln(2)

⇒ W = - (2.5)(8.314)(298)(0.693) = - 4293.3 J

⇒ Q = 4293.3 J

(2) W = 0

⇒ ΔU = Q = Cv*ΔT

∴ ΔT = 244 - 298 = - 54K

∴ Cv = 1.5*R = 12.471 J/mol.K

⇒ Q = (12.471)*(- 54)*(2.5) = - 1683.585 J

(3) ⇒ Wt = W(1) + W(2) = -4293.3 + 0 = - 4293.3 J

⇒ Qt = Q(1) + Q(2) = 4293.3 - 1683.585 = 2609.72 J

answer; i believe the correct answer is (c) /// is a homogeneous mixture of gaseous substance nitrogen,oxygen and smaller amounts of other substancesmixtures can be either ( homogeneous or heterogeneous)plz check first good luck

alkaline metals are lithium, sodium, rubidium, potassium, cesium and francium.

alkali metals have electronegativity from 0.7 to 1, lowest in periodic table of elements, which means that alkali metals (i group in periodic table) has positive oxidation number in compounds.

electronegativity is a chemical property that describes the tendency of an atom to attract a shared pair of electrons towards itself.

alkaline metals (far left in main group) have lowest ionizations energy and easy remove valence electrons,

for example, potassium is the alkali metal and has a single valence electron in the outer electron shell.

electron configuration of potassium is: ₁₉k 1s²2s²2p⁶3s²3p⁶4s¹.

they can not exist alone in nature, because they are very reactive.