Draw all the structural isomers for the molecular formula c4h9br. be careful not to draw any structures by crossing one line over another; the system needs to know where you intend connections to be between atoms.

There are four structural isomers with the molecular formula C₄H₉Br.

You start by writhing the linear carbon chain and the you start moving the bromide atom until you find all the compounds. In our case you have bromide atom in the position 1 and 2 on the carbon chain.

Then you branch the carbon chain and you have isobutane. Here the possible positions for bromide is 1 and 2 on the primary carbon chain.

c8h10 is your answerr