Chemistry, 16.09.2019 18:20, callieroberts1699
Asodium ion, na+, with a charge of 1.6×10−19c and a chloride ion, cl− , with charge of −1.6×10−19c, are separated by a distance of 1.1nm. how much work would be required to increase the separation of the two ions to an infinite distance?
Answers: 1
, where K is the Coulomb´s constant (
), 
= Charge 1 (Na+ in this case), 
is the charge 2 (Cl-) and r is the distance between both charges.
.![W=W_{f} -W_{i} =(K\frac{q_{(Na+)}q_{(Cl-)}rf}{r_{f} ^{2}})-(K\frac{q_{(Na+)}q_{(Cl-)}ri}{r_{i} ^{2}})=Kq_{(Na+)}q_{(Cl-)[\frac{1}{{r_{f}}} -\frac{1}{{r_{i}}}]](/tpl/images/0233/7563/c0380.png)
and rf= infinite distance![W=(9x10^{9})(1.6x10^{-19})(-1.6x10^{-19})[\frac{1}{\alpha }-\frac{1}{(1.1x10^{-9})}]=2.1x10^{-19}J](/tpl/images/0233/7563/01c0a.png)
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Asodium ion, na+, with a charge of 1.6×10−19c and a chloride ion, cl− , with charge of −1.6×10−19c,...
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