What experiment can be used to separate suspended solid silver chloride from the water in which it is suspended?

As the silver chloride is an insoluble compound in water, I can apply heat to water to make it evaporate and recover the chloride. You can also apply a filtration process to remove the liquid or centrifuge so the chloride can precipitate and remains at the bottom of the tube

Explanation:

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"