A100.0 g sample of aluminum released 1680 calories when cooled from 100.0c to 20.0 c what is the specific heat of the metal

The specific heat of aluminium is 0.8792 J/g °C  or 0.21 Cal/g °C

Explanation:

Step 1 : Write formule of specific heat

Q=mcΔT

with Q = heat transfer (J)

with m = mass of the substance

with c = specific heat ⇒ depends on material and phase ( J/g °C)

with ΔT = Change in temperature

For this case :

Q = 1680 Calories = 7033.824 J ( 1 calorie = 4.1868 J)

m = 100.0g

c= has to be determined

ΔT = 100 - 20 = 80°C

Step 2:  Calculating specific heat

⇒ via the formule Q=mcΔT

7033.824 J = 100g * c * 80

7033.824 = 8000 *c

c = 7033.824 /8000

c = 0,879228 J/g °C

or 0.21 Cal / g°C

The specific heat of aluminium is 0.8792 J/g °C  or 0.21 Cal/g °C

a c d and f

just finished the assignment

ill try to . no promises tho.

explanation: