What is the specific heat (j/g c)of a metal who’s temp increases by 3.0 c when 17.5 g of metal was heated with 38.5 j

0.733 J/g °C

Explanation:

Step 1 : Write formule of specific heat

Q = mc Δ T

with Q = heat transfer (J)

with m = mass of the substance

with c = specific heat ⇒ depends on material and phase ( J/g °C)

Δ T = Change in temperature

in this case :

Q = 38.5 J

m = 17.5g

c= has to be determined

Δ T = 3 (°C)

Step 2:  Calculating specific heat

⇒ via the formule Q = mc Δ T

38.5 J = 17.5g * c * 3

38.5 = 52.5 *c

c = 38.5 / 52.5

c = 0.733 J/g °C ⇒ 0.733 is reported to three significant digits due to the precision.

The specific heat of this metal is 0.733 J/g °C

answer: -

reaction:

na + cl ⇌ nacl

balanced chemical equation:

na + 2cl ⇌ nacl2

sodium + clorine goes to form sodium chloride (table salt).

the product is nacl2.

and the reactants are na and cl.

(note: if you don’t know what ⇌ means, read below: -

⇌(double head arrow) means reversible reaction).

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