For light with a frequency of 5.371 x 10^14 s^-1, what is the energy (in j)?

The energy is 3.559 * 10⁻¹⁹ J

Explanation:

For this problem we need to use Planck's equation, this equation describes the relationship between energy radiated by light (a photon, to be precise) and its frequency. The equation is:

E = h * v

Where E is energy (in Joules), h is Planck's constant (6.626 * 10⁻³⁴ J·s), and v is the frequency (in s⁻¹).

Now we solve the equation, using the data given in the problem:

E = 6.626 * 10⁻³⁴ J·s * 5.371 * 10¹⁴ s⁻¹ = 3.559 * 10⁻⁴⁷ J

Thus the energy is 3.559 * 10⁻¹⁹ J

the answer is barium and copper bromide