Assume that the complete combustion of one mole of glucose to carbon dioxide and water liberates 2870 kj/mol2870 kj/mol ( δ°′=−2870 kj/molδg°′=−2870 kj/mol ). if one contraction cycle in muscle requires 67 kj67 kj , and the energy from the combustion of glucose is converted with an efficiency of 39%39% to contraction, how many contraction cycles could theoretically be fueled by the complete combustion of one mole of glucose? round your answer to the nearest whole number.

Number of contraction cycles that could theoretically be fueled by the complete combustion of one mole of glucose is around 17

Explanation:

Energy released during the complete combustion of 1 mole glucose = 2870 kJ

Energy required/muscle contraction cycle = 67 kJ/contraction

Energy conversion efficiency = 39%

Actual amount of energy converted to contraction per mole of glucose is:

Total contraction cycles fueled by the above energy is:

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :