When solutions of silver nitrate and sodium chloride are mixed, a precipitation reaction occurs. what mass of precipitate can be produced from 1.14 l of a 0.269 m solution of silver nitrate reacting with excess sodium chloride?

Explanation:

The given precipitation reaction will be as follows.

Here, AgCl is the precipitate which is formed.

It is known that molarity is the number of moles present in a liter of solution.

Mathematically,       Molarity =

It is given that volume is 1.14 L and molarity is 0.269 M. Therefore, calculate number of moles as follows.

                    Molarity =

                     0.269 M =

                    no. of moles = 0.306 mol

As molar mass of AgCl is 143.32 g/mol. Also, relation between number of moles and mass is as follows.

               No. of moles =

                   0.307 mol =

                           mass = 43.99 g

Thus, we can conclude that mass of precipitate produced is 43.99 g.

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explanation:

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