An unbalanced chemical equation for the reaction of boron fluoride with lithium sulfite is shown below.
bf3 +li so3 → b2(so3)3 + lif
what is the coefficient of lithium fluoride in the balanced chemical reaction?
1

6

Explanation:

You have the unbalanced chemical reaction:

BF3 + Li2SO3 ⇒ B2(SO3)3 + LiF

Knowing that there are 2 atoms of boron in the products, we need to adjust that element putting 2 as coefficient of BF3.

2BF3 + Li2SO3 ⇒ B2(SO3)3 + LiF

Then, we need to balance fluor. There are 6 atoms of F in the reactants, for that reason, we write 6 in the lithium fluoride.

2BF3 + Li2SO3 ⇒ B2(SO3)3 + 6LiF

Finally, sulfur and oxygen have to be adjusted. 3 before lithium sulfite is enough to balance the chemical reaction.

2BF3 + 3Li2SO3 ⇒ B2(SO3)3 + 6LiF

1.consider the following balanced equation and answer parts a through. show calculations for each part.  

3 ag(s) + 4 hno3(aq) → 3 agno3(aq) + no(g) + 2 h2o(l)  

a. calculate the number of moles of agno3 produced by the reaction of 3 moles of ag with excess hno3. if the number to the left of the compound represents the number of moles of the compound which are present, then 3 moles of ag react with 4 moles hno3 to produce 3 moles agno3 (aq).

so the answer to a would be 3 moles.

b. calculate the number of moles of agno3 produced by the reaction of 108 grams of ag with excess hno3.  

i'm not sure how to plug in the grams of silver into an equation using moles to find how many moles are produced.

c. calculate the number of grams of agno3 produced by the reaction of 108 grams of ag with excess hno3  

d. calculate the number of moles of no produced as a byproduct of the reaction of 108 grams of ag with excess hno3.  

e. calculate the number of grams of no produced as a byproduct starting with 108 grams of ag and excess hno3.  

explanation:

c- cold periods in earth's history during which glaciers covered much of the surface.

explanation: