During a laboratory experiment, you discover that an enzyme-catalyzed reaction has a ∆g of -20 kcal/mol. if you double the amount of enzyme in the reaction, what will be the ∆g for the new reaction?

dG will be the same -20 kcal/mol

Explanation:

The dG can be expressed in terms of the G(products) - G(reactants). If the amount of enzyme is doubled the Gibbs energy of the reactants and products will be the same, so the substraction dG has the same value

im not exactly sure but i think its b!