Solids like silver chloride (agcl) dissolve in water according to the temperature and solubility (g/l or mg/l). if the solubility of agcl at 25 °c is 2.5 g agcl(s) in 1.3 x 103 l of water, what mass (in milligrams) of agcl will dissolve in 1.0 l of water at the same temperature?

1.92 mg

Explanation:

This is a simple rule of three, the only conversion that you need to do is from grams into milligrams = 2.5 g = 2500 mg.

Also remember to convert the scientific notation of liters of water = 1.3 x103 L = 13000 L

So, with this information, you can do the mathematical calculation.

2500 mg  -  1300 L water

      X        - 1 L

X = (1 x 2500) /1300

X = 1.92 mg

the answer would be a

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