The correct answer is Option 5.
Explanation:
To calculate the number of moles, we use the equation:
Β
For calcium cyanamide:
Given mass of calcium cyanamide = 65 g
Molar mass of calcium cyanamide = 80.1 g/mol
Putting values in above equation, we get:
Moles of water = 4.0 moles
The chemical equation for the reaction of calcium cyanide and water follows:
By Stoichiometry of the reaction:
1 mole of calcium cyanamide reacts with 3 moles of water.
So, 0.811 moles of calcium cyanamide will react with = of water.
As, given amount of water is more than the required amount. So, it is considered as an excess reagent.
Thus, calcium cyanamide is considered as a limiting reagent because it limits the formation of product.
By Stoichiometry of the reaction:
1 mole of calcium cyanamide produces 2 moles of ammonia.
So, 0.811 moles of calcium cyanamide will produce = of ammonia.
Hence, the correct answer is Option 5.