2-phosphoglycerate(2pg) is converted to phosphoenolpyruvate (pep) by the enzyme enolase. the standard free energy change(deltago’) for this reaction is +1.7 kj/mol. if the cellular concentrations are 2pg = 0.5 mm and pep = 0.1 mm, what is the free energy change at 37 oc for the reaction 2pg ↔ pep
5.8 kj/mol
-5.8 kj/mol
+2.4 kj/mol
-2.4 kj/mol
-4146.4 kj/mol
+4146.4 kj/mol

-2.4 kJ/mol

Explanation:

We can relate to according to:

Where [products] is the concentration of products, [reagents] is the concentrarion of reagents, n and m are the corresponding stoichiometric coefficients, T is the temperature in Kelvin and R is the gas constant.

Converting 37°C to Kelvin by adding 273, mM to M dividing by 1000, and substituting we get:

That gives us a value of -2.4 kJ/mol, the fouth option.

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