What is the molarity of the hydrochloric acid if 31.00 ml of hcl is required to neutralize 0.525 g of sodium carbonate? 2hcl(aq)+na2co3(aq)→2nacl(aq)+h2o(l )+co2(g)

The molarity of HCl solution is 0.08 M.

Explanation:

To calculate the number of moles, we use the equation:

Given mass of sodium carbonate = 0.525 g

Molar mass of sodium carbonate = 106 g/mol

Putting values in above equation, we get:

The chemical reaction for the formation of chromium oxide follows the equation:

By Stoichiometry of the reaction:

1 mole of sodium carbonate reacts with 2 moles of HCl

So, 0.005 moles of sodium carbonate will react with = of HCl

To calculate the molarity of HCl, we use the equation:

We are given:

Moles of HCl = 0.0025 moles

Volume of solution = 31.00 mL = 0.031 L      (Conversion factor:  1L = 1000 mL)

Putting values in above equation, we get:

Hence, the molarity of HCl solution is 0.08 M.

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