Consider the general form of a reversible reaction to be: where the double arrow means the reaction can proceed in both the forward and reverse direction. if the equilibrium constant for the forward reaction is defined as: -, what is the equilibrium constant for the reverse reaction? a) it is exactly the same. namely b) it is just the products of the reactants. namely, c) it is equal to the reciprocal of the forward equilibrium constant. that is d) the reverse equilibrium constant cannot be determined. a) bi od) cl

Option (c) is the correct answer.

Explanation:

A reversible reaction is defined as the reaction in which rate of forward reaction is equal to the rate of backward reaction.

In general, an equilibrium or reversible reaction will be as follows.

As equilibrium constant is the ratio of concentration of product over reactants.

Hence, equilibrium constant in forward direction for this reaction will be as follows.

                .......... (1)

On the other hand, equilibrium constant of backward reaction is as follows.

                       =  ............ (2)

This means that equilibrium constant of backward reaction is reciprocal of equilibrium constant of forward reaction.

Thus, we can conclude that the equilibrium constant for the reverse reaction is equal to the reciprocal of the forward equilibrium constant.

h let me think

assuming that your periodic table has eighteen columns, you should highlight   the four elements in the third column from the left of the table.

neutral atoms of elements after calcium contain d electrons. the energy of d orbitals of a particular main shell lies between the energy of the s and p orbitals of the next main shell. for example, electrons in the have energy higher than those in the orbital while lower than those of the orbital.

by the aufbau principle, electrons fill orbitals one at a time, starting from those of the lowest energy. the orbital is therefore filled right after orbitals and before orbitals.  

potassium has electron configuration and calcium . the s orbital of a main shell holds a maximum of two electrons. the next element would thus have the electron configuration and satisfy the requirements.

a neutral atom of the element contains three electrons on top of the most recent noble gas element. it should thus be placed in the third column of the periodic table. both scandium and yttrium would satisfy the conditions. an aufbau diagram indicates that the 4f orbital is filled before the 5d. however, it appears that exceptions exists for both lanthanum and actinium. neutral atoms of the two d-block elements also demonstrate the and should be highlighted as well.