Using the supplemental data, calculate the standard enthalpy change (in kj/mol) for each of the following reactions. (a) 2 na(s) + i2(g) → 2 nai(s) kj/mol (b) 2 koh(s) + co2(g) → k2co3(s) + h2o(g) kj/mol (c) b2o3(s) + 3 h2(g) → 2 b(s) + 3 h2o(l) kj/mol (d) ni(s) + cl2(g) → nicl2(s) kj/mol

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.

brian made this table to organize his notes on changes of state. depostion is a change of state that has the wrong energy change listed. it is utilized to collect data as a portion of the development means and in restricted conditions which may be applied at test.

a deposition in the authority of the united states or research for development in the authority of canada includes the catching of affirmed. the out-of-court verbal assertion of a spectator that may be lessened to a printed record for succeeding application for discovery purposes.