Menthol is composed of c, h, and o. a 0.1005-g sample of menthol is combusted in oxygen, producing 0.2829 g of co2 and 0.1159 g of h2o. what is the empirical formula of menthol?

The empirical formula for the given organic compound is

Explanation:

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of

Mass of

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 0.2829 g of carbon dioxide, of carbon will be contained.

In 18 g of water, 2 g of hydrogen is contained.

So, in 0.1159 g of water, of hydrogen will be contained.

To formulate the empirical formula, we need to follow some steps:

Moles of Carbon =

Moles of Hydrogen =

Moles of Oxygen =

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.0064 moles.

For Carbon =

For Hydrogen  =

For Oxygen  =

The ratio of C : H : O = 1 : 2 : 1

Hence, the empirical formula for the given compound is

the answer is   c.) 1575 j.

explanation:

each  column  of the  table  is called a group. elements in a group share similar properties. groups are  read  from  top  to  bottom. metal. metalloid. nonmetal. solid. liquid. gas. fe. hg. o.  2. 3. 4. 5. 6. 7. 8. 9.  2. beryllium. 9.012. 4.  sodium. 22.990.  11. 3.  magnesium. 24.305.  12.  potassium. 39.098.  19. 4.  calcium. 40.078.  20. i guess  i