Which equation correctly represents the electron affinity of the cesium atom? cs (g) cs1 (g)+2 e cs+1 (g) cs (g) + 1e cs (g) ocs+1 (g) +1e cs1 (g) cs (g) +1e cs (g) cs1 (g) + 1e

Answer : The correction equation will be:

Explanation :

Electron affinity : It is defined as the addition of electron to the atom or to the ion. The atom or ion is always in gaseous phase.

In other words we can say that, the gaining of electrons is said to be an electron affinity.

As, the given element is a metal given in cationic form, so its positive ion will gain an electron to form a neutral atom.

The balanced and correct equation for electron affinity of the cesium ion will be:

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied