How much heat, in joules and in calories, must be added to a 75.0- g iron block with a specific heat of 0.449 j/g degree cecius to increas its temperature from 25 degree celcius to its melting temperature of 1535 dgree celcius?

The heat required by iron is 50849.25 Joules or 12152.97 Cal.

Explanation:

To calculate the amount of heat released or absorbed, we use the equation:

where,

q = heat absorbed

m = mass of iron = 75 g

c = specific heat capacity of iron = 0.449 J/g.°C

= change in temperature =

Putting values in above equation, we get:

Converting the value from joules to calories, we use the conversion factor:

1 J = 0.239 Cal

So,

Hence, the heat required by iron is 50849.25 Joules or 12152.97 Cal.

the mass of the cathode increases because ions from the solution get reduced to atoms and become part of the cathode.

explanation:

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