What volume of a 0.3300m solution of sodium hydroxide would br ruired to titrate 15.00 ml of 0.1500 m oalic acid?
c2o4h2 + 2naoh ? na2c2o4 + 2h2o

3.41 mL

Explanation:

At equivalence point  from the reaction given,

Moles of = 2 × Moles of NaOH

Considering

Given  that:

So,  

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explanation:

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm